Chemical Kinetics Surface Chemistry Test Online MCQs

1. for a first order reaction, to obtain a positive slope, we need to plot {where [A] is the concentration of reactant A}

2. The electrical charge on a colloidal particle is observed by

3. The density of gold is 19 g/cm³. If 1.9 x 10⁻⁴ g of gold is dispersed in one liter of water to give a sol having spherical gold particles of radius 10nm, then the number of gold particles per mm³ of the sol will be:

4. The rate constant k, for the reaction N₂O₅(g) → 2NO₂(g)+1/2 O₂(g) is 1.3 x 10⁻²s⁻¹. Which equation given below describes the change of [N₂O₅] with time? [N₂O₅]₀ and [N₂O₅]_t correspond to concentration of N₂O₅ initially and at time t.

(a) [N₂O₅]_t= [N₂O₅]₀ + kt

(b) [N₂O₅]₀ = [N₂O₅]_t e^kt

(c) Log [N₂O₅]_t = log [N₂O₅]₀ + kt

(d) In [N₂P₅]₀/[N₂P₅] _t = kt

5. Which of the following ions will have the minimum coagulating value for the sol obtained by adding FeC1₃ solution to slight excess of NaOH

6. The physical adsorption of gases on the solid surface is due to:

7. T₅₀ of first –order reaction is 10 min. starting with 10 mol L⁻¹, rate after 20 min is:

8. Which of the following electrolyte will have maximum flocculation value for Fe(OH)₃ sol?

9. The size of colloidal particle is

10. The rate constant for the reaction, 2N₂O₅ → 4NO₂ + O₂ is 3.0 x 10⁻⁴ s⁻¹. If start made with 1.0 mol L⁻¹ of N₂O₅, calculate the rate of formation of NO₂ at the moment of the reaction when concentration of O₂ is 0.1 mol L⁻¹.

11. The movement of colloidal particles, under applied electric current is known as:

12. Purple of cassius is colloidal solution of:

13. For the reaction, 2N₂O₅ → 4NO₂ + O₂ the rate of reaction is:

14. The rate constant of first order reaction is 3 x 10⁻⁶ per second. The initial concentration is 0.10 M. The initial rate is:

15. A catalyst