Chemistry

1. mark review The size of colloidal particle is

10⁻¹² to 10⁻¹⁹ m

10⁻⁶ to 10⁻⁹ m

10⁻³ to 10⁻¹² m

10⁻³ to 10⁻⁹ m

Question 1 of 15

2. mark review Which of the following molecules is most suitable to disperse benzene in water?

(a)

(b)

(c)

(d)

Question 2 of 15

3. mark review A catalyst

Increases the forward and backward reaction at different speeds

Follows same mechanism for the reaction

Lowers the activation energy

Changes the equilibrium constant

Question 3 of 15

4. mark review Lyophilic colloids are stable due to:

Layer of dispersion medium on the particle

Small size of the particle

Large size of the particle

Charge on the particle

Question 4 of 15

5. mark review Which of the following is not a green house gas?

Water vapour

Carbon dioxide

Methane

Oxygen

Question 5 of 15

6. mark review Purple of cassius is colloidal solution of:

Gold

Mercury

Lead

Silver

Question 6 of 15

7. mark review Which of the following electrolyte will have maximum flocculation value for Fe(OH)₃ sol?

NaC1

Na₂S

(NH₄)₃PO₄

K₂SO₄

Question 7 of 15

8. mark review T₅₀ of first –order reaction is 10 min. starting with 10 mol L⁻¹, rate after 20 min is:

0.0693 x 10 mol L⁻¹ min⁻¹

0.0693 mol L⁻¹ min⁻¹

0.0693 x 2.5 mol L⁻¹ min⁻¹

0.0693 x 5 mol L⁻² min⁻¹

Question 8 of 15

9. mark review For the reaction: H₂ + C1₂ 2HC1 the order of reaction is:

Question 9 of 15

10. mark review The rate constant for the reaction, 2N₂O₅ → 4NO₂ + O₂ is 3.0 x 10⁻⁴ s⁻¹. If start made with 1.0 mol L⁻¹ of N₂O₅, calculate the rate of formation of NO₂ at the moment of the reaction when concentration of O₂ is 0.1 mol L⁻¹.

2.7 x 10⁻⁴ mol L⁻¹ s⁻¹

4.8 x 10⁻⁴ mol L⁻¹ s⁻¹

9.6 x 10⁻⁴ mol L⁻¹ s⁻¹

2.4 x 10⁻⁴ mol L⁻¹ s⁻¹

Question 10 of 15

11. mark review The first order rate constant for a certain reaction increases from 1.667 x 10⁻⁶ s⁻¹ at 727°C to 1.667 x 10⁻⁴ s⁻¹ at 1571°C. The rate constant at 1150°C, assuming constancy of activation energy over the given temperature range is [Given: log 19.9 = 1.299]

1.139 x 10⁻⁵s⁻¹

3.318 x 10⁻⁵s⁻¹

3.911 x 10⁻⁵s⁻¹

1.193 x 10⁻⁵s⁻¹

Question 11 of 15

12. mark review Milk is colloid in which

Liquid is dispersed in liquid

Sugar is dispersed in liquid

Gas is dispersed in liquid

Sugar is dispersed in water

Question 12 of 15

13. mark review The physical adsorption of gases on the solid surface is due to:

Van der waal’s forces

Covalent bond

Ionic bond

Hydrogen bond

Question 13 of 15

14. mark review Which of the following statement is true for the reaction, H₂ + Br₂ → 2HBr The rate law is dx/dt = k[H₂][Br₂]^1/2:

Molecularity of the reaction is 2

Order of reaction is 1.5

By increasing the concentration of Br₂ four times the rate of reaction is doubled.

All the above are correct.

Question 14 of 15

15. mark review The colligative property is not represented by:

Relative lowering of vapour pressure

Optical activity

Osmotic pressure

Elevation in boiling point

Question 15 of 15

Test Name	Chemical Kinetics Surface Chemistry Test
Subject	Chemistry
Test Type	MCQs
Total Question	15
Total Marks	30
Total Time	15 Mints
Test Help For	Chemistry Subject Test. All Jobs and Recruitment tests Prep. BDS and Medical Test Preparation. Engineering Test Prep. B Tech Test preparation.

Test By Subject	Chemistry
Test By Topics	Chemistry Subject

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Chemical Kinetics Surface Chemistry Test Online MCQs

Chemical Kinetics Surface Chemistry Test Online MCQs

Chemistry

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