Home / Tests / Chemical Kinetics Surface Chemistry Test Online MCQs

Chemical Kinetics Surface Chemistry Test Online MCQs

Test Name Chemical Kinetics Surface Chemistry Test
Subject Chemistry
Test Type MCQs
Total Question 15
Total Marks 30
Total Time 15 Mints
Test Help For
  • Chemistry Subject Test.
  • All Jobs and Recruitment tests Prep.
  • BDS and Medical Test Preparation.
  • Engineering Test Prep.
  • B Tech Test preparation.

Get Chemical Kinetics Surface Chemistry Test Online multiple choice questions over here to check your intellectual level and increase your knowledge as well. Attempt all the MCQs to prepare for the entrance tests, NEET and AIIMS admission tests, engineering tests, medical tests, competitive tests and recruitment tests.

Chemical Kinetics Surface Chemistry Test Online MCQs


1. The physical adsorption of gases on the solid surface is due to:


Question 1 of 15

2. The rate constant of first order reaction is 3 x 10⁻⁶ per second. The initial concentration is 0.10 M. The initial rate is:


Question 2 of 15

3. Lyophilic colloids are stable due to:


Question 3 of 15

4. for a first order reaction, to obtain a positive slope, we need to plot {where [A] is the concentration of reactant A}


Question 4 of 15

5. Milk is colloid in which


Question 5 of 15

6. For reaction aA xP, when [A] = 2.2 mM, the rate was found to be 2.4 mMs⁻. On reducing concentration of A to half, the rate changes to 0.6  mMs⁻. The order of reaction with respect to A is:


Question 6 of 15

7. The rate constant k, for the reaction N₂O₅(g)2NO₂(g)+1/2 O₂(g) is 1.3 x 10⁻²s⁻¹. Which equation given below describes the change of [N₂O₅] with time? [N₂O₅]₀ and [N₂O₅]t correspond to concentration of N₂O₅ initially and at time t.

(a) [N₂O₅]t= [N₂O₅]₀ + kt

(b) [N₂O₅]₀ = [N₂O₅]t ekt

(c) Log [N₂O₅]t = log [N₂O₅]₀ + kt

(d) In [N₂P₅]₀/[N₂P₅] t = kt

Question 7 of 15

8. The electrical charge on a colloidal particle is observed by


Question 8 of 15

9. For the reaction: H₂ + C1₂  032HC1 the order of reaction is:


Question 9 of 15

10. T₅₀ of first –order reaction is 10 min. starting with 10 mol L⁻¹, rate after 20 min is:


Question 10 of 15

11. Which of the following molecules is most suitable to disperse benzene in water?

(a) 35

(b) 36

(c)  37

(d) 38

Question 11 of 15

12. The density of gold is 19 g/cm³. If 1.9 x 10⁻⁴ g of gold is dispersed in one liter of water to give a sol having spherical gold particles of radius 10nm, then the number of gold particles per mm³ of the sol will be:


Question 12 of 15

13. The rate constant for the reaction, 2N₂O₅ 4NO₂ + O₂ is 3.0 x 10⁻⁴ s⁻¹. If start made with 1.0 mol L⁻¹ of N₂O₅, calculate the rate of formation of NO₂ at the moment of the reaction when concentration of O₂ is 0.1 mol L⁻¹.


Question 13 of 15

14. A catalyst


Question 14 of 15

15. For the reaction, 2N₂O₅ 4NO₂ + O₂ the rate of reaction is:


Question 15 of 15


Test By Subject
Test By Topics
Have any Problem or Error please mention in below comments section.

Leave a Reply

Your email address will not be published. Required fields are marked *