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# Chemical Kinetics Surface Chemistry Test Online MCQs

 Test Name Chemical Kinetics Surface Chemistry Test Subject Chemistry Test Type MCQs Total Question 15 Total Marks 30 Total Time 15 Mints Test Help For Chemistry Subject Test. All Jobs and Recruitment tests Prep. BDS and Medical Test Preparation. Engineering Test Prep. B Tech Test preparation.

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## Chemistry

1. The physical adsorption of gases on the solid surface is due to:

Question 1 of 15

2. The rate constant of first order reaction is 3 x 10⁻⁶ per second. The initial concentration is 0.10 M. The initial rate is:

Question 2 of 15

3. Lyophilic colloids are stable due to:

Question 3 of 15

4. for a first order reaction, to obtain a positive slope, we need to plot {where [A] is the concentration of reactant A}

Question 4 of 15

5. Milk is colloid in which

Question 5 of 15

6. For reaction aA xP, when [A] = 2.2 mM, the rate was found to be 2.4 mMs⁻. On reducing concentration of A to half, the rate changes to 0.6  mMs⁻. The order of reaction with respect to A is:

Question 6 of 15

7. The rate constant k, for the reaction N₂O₅(g)2NO₂(g)+1/2 O₂(g) is 1.3 x 10⁻²s⁻¹. Which equation given below describes the change of [N₂O₅] with time? [N₂O₅]₀ and [N₂O₅]t correspond to concentration of N₂O₅ initially and at time t.

(a) [N₂O₅]t= [N₂O₅]₀ + kt

(b) [N₂O₅]₀ = [N₂O₅]t ekt

(c) Log [N₂O₅]t = log [N₂O₅]₀ + kt

(d) In [N₂P₅]₀/[N₂P₅] t = kt

Question 7 of 15

8. The electrical charge on a colloidal particle is observed by

Question 8 of 15

9. For the reaction: H₂ + C1₂ 2HC1 the order of reaction is:

Question 9 of 15

10. T₅₀ of first –order reaction is 10 min. starting with 10 mol L⁻¹, rate after 20 min is:

Question 10 of 15

12. The density of gold is 19 g/cm³. If 1.9 x 10⁻⁴ g of gold is dispersed in one liter of water to give a sol having spherical gold particles of radius 10nm, then the number of gold particles per mm³ of the sol will be:

Question 12 of 15

13. The rate constant for the reaction, 2N₂O₅ 4NO₂ + O₂ is 3.0 x 10⁻⁴ s⁻¹. If start made with 1.0 mol L⁻¹ of N₂O₅, calculate the rate of formation of NO₂ at the moment of the reaction when concentration of O₂ is 0.1 mol L⁻¹.

Question 13 of 15

14. A catalyst

Question 14 of 15

15. For the reaction, 2N₂O₅ 4NO₂ + O₂ the rate of reaction is:

Question 15 of 15

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